Title
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:
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Mengenal dan Menghitung Cepat IP Address
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Issue Date
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03 Februari 2017
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Prepared By
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:
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Rika Alfiani
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Teacher
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:
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Maman Hariana, S.Kom
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No. Jobsheet
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:
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26
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SMK AL-BAHRI 2
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||
Mengenal dan Menghitung Cepat IP Address
IP Address ada 3 kelas :
- 0.0.0.0 = 127.255.255.255
- 128.0.0.0 = 192.255.255.255
- 192.0.0.0 = 223.255.255.255
IP Public yaitu IP yang terdeteksi dan terregistrasi
di Internet.
IP Private yaitu IP yang diterapkan di LAN dan tidak
terregistrasi di Internet.
255.255.255.255
128 64 32
16 8 4 2 1
Menghitung IP Address Kelas A
- 10.0.0.0/14 catatan : 2* = 2 pangkat x
||||||||.||||||00.00000000.00000000 = 2y-2 = 2 pangkat
y-2
255.252.0.0
Jumlah Subnet = 2* = 2 (6) = 64
Jumlah Host = 2y-2 = 2 (18)-2 = 262142
Blok Subnet = 256-252 = 4 (0,4,8,12,16,.....)
Tabel yang Valid :
Subnetting =
10.0.0.0
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10.4.0.0
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10.8.0.0
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10.12.0.0
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Host Pertama
= 10.0.0.1
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10.4.0.1
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10.8.0.1
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10.12.0.1
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Host Terakhir
= 10.3.255.254
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10.7.255.254
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10.11.255.254
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10.15.255.254
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Broadcast =
10.3.255.255
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10.7.255.255
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10.11.255.255
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10.15.255.255
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- 10.0.0.0/20
||||||||.||||||||.||||0000.00000000
255.255.240.0
Jumlah Subnet = 2* = 2 (12) = 4096
Jumlah Host = 2y-2 = 2 (12)-2 = 4094
Blok Subnet = 256-240 = 16 (0,16,32,48,64,....)
Tabel yang Valid :
Subnetting =
10.0.0.0
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10.0.16.0
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10.0.32.0
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10.0.48.0
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Host Pertama
= 10.0.0.1
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10.0.16.1
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10.0.32.1
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10.0.48.1
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Host Terakhir
= 10.0.15.254
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10.0.31.254
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10.0.47.254
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10.0.63.254
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Broadcast =
10.0.15.255
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10.0.31.255
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10.0.47.255
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10.0.63.255
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- 10.0.0.0/28
|||||||.||||||||.||||||||.||||0000
255.255.255.240
Jumlah Subnet = 2* = 2 (20) = 1048576
Jumlah Host = 2y-2 = 2 (4)-2 = 14
Blok Subnet = 256-240 = 16 (0,16,32,48,64,....)
Tabel yang Valid :
Subnetting =
10.0.0.0
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10.0.0.16
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10.0.0.32
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10.0.0.48
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Host Pertama
= 10.0.0.1
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10.0.0.17
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10.0.0.33
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10.0.0.49
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Host Terakhir
= 10.0.0.14
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10.0.0.30
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10.0.0.46
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10.0.0.62
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Broadcast =
10.0.0.15
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10.0.0.31
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10.0.0.47
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10.0.0.63
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Menghitung IP Address Kelas B
- 172.30.0.0/20 catatan : 2* = 2 pangkat x
||||||||.||||||||.||||0000.00000000 = 2y-2 = 2 pangkat
y-2
255.255.240.0
Jumlah Subnet = 2* = 2 (4) = 16
Jumlah Host = 2y-2 = 2 (12)-2 = 4094
Blok Subnet = 256-240 = 16 (0,16,32,48,64,....)
Tabel yang Valid :
Subnetting =
172.30.0.0
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172.30.16.0
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172.30.32.0
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172.30.48.0
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Host Pertama
= 172.30.0.1
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172.30.16.1
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172.30.32.1
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172.30.48.1
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Host Terakhir
= 172.30.15.254
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172.30.31.254
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172.30.47.254
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172.30.63.254
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Broadcast =
172.30.15.255
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172.30.31.255
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172.30.47.255
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172.30.63.255
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- 172.20.0.0/17
||||||||.||||||||.|0000000.00000000
255.255.128.0
Jumlah Subnet = 2* = 2 (1) = 2
Jumlah Host = 2y-2 = 2 (15)-2 = 32766
Blok Subnet = 256-128 = 128 (0,128,....)
Tabel yang Valid :
Subnetting =
172.20.0.0
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172.20.128.0
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Host Pertama
= 172.20.0.1
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172.20.128.1
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Host Terakhir
= 172.20.127.254
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172.20.255.254
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Broadcast =
172.20.127.255
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172.20.255.255
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- 172.20.0.0/25
||||||||.||||||||.||||||||.|0000000
255.255.255.128
Jumlah Subnet = 2* = 2 (9) = 512
Jumlah Host = 2y-2 = 2 (7)-2 = 126
Blok Subnet = 256-128 = 128 (0,128,....)
Tabel yang Valid :
Subnetting =
172.20.0.0
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172.20.0.128
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172.20.1.0
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172.20.1.128
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Host Pertama
= 172.20.0.1
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172.20.0.129
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172.20.1.1
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172.20.1.129
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Host Terakhir
= 172.20.0.126
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172.20.0.254
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172.20.1.126
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172.20.1.254
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Broadcast =
172.20.0.127
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172.20.0.255
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172.20.1.127
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172.20.1.255
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Menghitung IP Address Kelas C
- 192.168.50.0/30 catatan : 2* = 2 pangkat x
||||||||.||||||||.||||||||.||||||00 = 2y-2 = 2 pangkat
y-2
255.255.255.252
Jumlah Subnet = 2* = 2 (6) = 64
Jumlah Host = 2y-2 = 2 (2)-2 = 2
Blok Subnet = 256-252 = 4 (0,4,8,12,16,.....)
Tabel yang Valid :
Subnetting =
192.168.50.0
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192.168.50.4
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192.168.50.8
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192.168.50.12
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Host Pertama
= 192.168.50.1
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192.168.50.5
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192.168.50.9
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192.168.50.13
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Host Terakhir
= 192.168.50.2
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192.168.50.6
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192.168.50.10
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192.168.50.14
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Broadcast =
192.168.50.3
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192.168.50.7
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192.168.50.11
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192.168.50.15
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